1
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
What is the molar solubility of Al(OH)3 in 0.2 M NaOH solution ? Given that, solubility product of Al(OH)3 = 2.4 × 10–24 :
A
3 × 10–22
B
3 × 10–19
C
12 × 10–21
D
12 × 10–22
2
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Glucose and Galactose are having identical configuration in all the positions except position
A
C–5
B
C–3
C
C–2
D
C–4
3
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product of the following reaction is : JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 126 English
A
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 126 English Option 1
B
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 126 English Option 2
C
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 126 English Option 3
D
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 126 English Option 4
4
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If ey + xy = e, the ordered pair $$\left( {{{dy} \over {dx}},{{{d^2}y} \over {d{x^2}}}} \right)$$ at x = 0 is equal to :
A
$$\left( {{1 \over e}, - {1 \over {{e^2}}}} \right)$$
B
$$\left( { - {1 \over e},{1 \over {{e^2}}}} \right)$$
C
$$\left( { - {1 \over e}, - {1 \over {{e^2}}}} \right)$$
D
$$\left( {{1 \over e},{1 \over {{e^2}}}} \right)$$
JEE Main Papers
2023
2021
EXAM MAP