1
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The increasing order of the pKb of the following compound is : JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Basics of Organic Chemistry Question 221 English
A
(C) < (A) < (D) < (B)
B
(B) < (D) < (C) < (A)
C
(B) < (D) < (A) < (C)
D
(A) < (C) < (D) < (B)
2
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major products of the following reaction are : JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 219 English
A
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 219 English Option 1
B
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 219 English Option 2
C
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 219 English Option 3
D
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 219 English Option 4
3
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Enthalpy of sublimation of iodine is 24 cal g–1 at 200 oC. If specific heat of I2(s) and l2 (vap) are 0.055 and 0.031 cal g–1K –1 respectively, then enthalpy of sublimation of iodine at 250 oC in cal g–1 is :
A
2.85
B
22.8
C
11.4
D
5.7
4
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Given

CO3+ + e $$ \to $$ CO2+ ; Eo = + 1.81 V

Pb4+ + 2e $$ \to $$ Pb2+ ; Eo = + 1.67 V

Ce4+ + e $$ \to $$ Ce3+ ; Eo = + 1.61 V

Bi3+ + 3e $$ \to $$ Bi ; Eo = + 0.20 V

Oxidizing power of the species will increase in the order :
A
Co3+ < Ce4+ < Bi3+ < Pb4+
B
Co3+ < Pb4+ < Ce4+ < Bi3+
C
Ce4+ < Pb4+ < Bi3+ < Co3+
D
Bi3+ < Ce4+ < Pb4+ < Co3+

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