1
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product(s) obtained in the following reaction is/are :
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 158 English
A
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 158 English Option 1
B
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 158 English Option 2
C
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 158 English Option 3
D
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 158 English Option 4
2
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the following reaction; xA $$ \to $$ yB
$${\log _{10}}\left[ { - {{d\left[ A \right]} \over {dt}}} \right] = {\log _{10}}\left[ {{{d\left[ B \right]} \over {dt}}} \right] + 0.3010$$
'A' and 'B' respectively can be :
A
n-Butane and Iso-butane
B
C2H4 and C4H8
C
C2H4 and C6H6
D
N2O4 and NO2
3
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product of the following addition reaction is :
H3C–CH=CH2 $$\buildrel {C{l_2}/{H_2}O} \over \longrightarrow $$
A
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Hydrocarbons Question 92 English Option 1
B
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Hydrocarbons Question 92 English Option 2
C
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Hydrocarbons Question 92 English Option 3
D
JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Hydrocarbons Question 92 English Option 4
4
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An ideal gas is allowed to expand form 1 L to 10 L against a constant external pressure of I bar. The work done in kJ is :
A
+10.0
B
–0.9
C
– 2.0
D
– 9.0
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