1
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a constant speed of 1 cm s-1. At some instant, a part of L is in a uniform magnetic field of 1 T, perpendicular to the plane of the loop. If the resistance of L is 1.7 $$\Omega $$, the current in the loop at that instant will be close to : JEE Main 2019 (Online) 12th April Morning Slot Physics - Electromagnetic Induction Question 87 English
A
115 $$\mu $$A
B
170 $$\mu $$A
C
60 $$\mu $$A
D
150 $$\mu $$A
2
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The truth table for the circuit given in the fig. is: JEE Main 2019 (Online) 12th April Morning Slot Physics - Semiconductor Question 141 English
A
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 1 \cr 1 & 0 & 1 \cr 1 & 1 & 1 \cr } } \right|$$
B
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 0 \cr 1 & 0 & 0 \cr 1 & 1 & 0 \cr } } \right|$$
C
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 1 \cr 1 & 0 & 0 \cr 1 & 1 & 0 \cr } } \right|$$
D
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 0 \cr 0 & 1 & 0 \cr 1 & 0 & 1 \cr 1 & 1 & 1 \cr } } \right|$$
3
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A galvanometer of resistance 100 $$\Omega $$ has 50 divisions on its scale and has sensitivitv of 20 $$\mu $$A/division. It is to be converted to a voltmeter with three ranges of 0-2V, 0-10 V and 0-20 V. The appropriate circuit to do so is
A
JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 221 English Option 1
B
JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 221 English Option 2
C
JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 221 English Option 3
D
JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 221 English Option 4
4
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A point dipole $$\overrightarrow p = - {p_0}\widehat x$$ is kept at the origin. The potential and electric field due to this dipole on the y-axis at a distance d are, respectively: (Take V= 0 at infinity)
A
$${{\left| {\overrightarrow p } \right|} \over {4\pi { \in _0}{d^2}}},{{ - \overrightarrow p } \over {4\pi { \in _0}{d^3}}}$$
B
$$0,{{\overrightarrow p } \over {4\pi { \in _0}{d^3}}}$$
C
$${{\left| {\overrightarrow p } \right|} \over {4\pi { \in _0}{d^2}}},{{\overrightarrow p } \over {4\pi { \in _0}{d^3}}}$$
D
$$0,{{ - \overrightarrow p } \over {4\pi { \in _0}{d^3}}}$$
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