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JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
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When M1 gram of ice at –10oC (specific heat = 0.5 cal g–1 oC–1 ) is added to M2 gram of water at 50C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in cal g–1 is :
A
$${{50{M_2}} \over {{M_1}}} - 5$$
B
$${{50{M_2}} \over {{M_1}}}$$
C
$${{5{M_2}} \over {{M_1}}} - 5$$
D
$${{5{M_1}} \over {{M_2}}} - 50$$
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