1
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product of the following reaction is : JEE Main 2019 (Online) 10th April Morning Slot Chemistry - Compounds Containing Nitrogen Question 206 English
A
JEE Main 2019 (Online) 10th April Morning Slot Chemistry - Compounds Containing Nitrogen Question 206 English Option 1
B
JEE Main 2019 (Online) 10th April Morning Slot Chemistry - Compounds Containing Nitrogen Question 206 English Option 2
C
JEE Main 2019 (Online) 10th April Morning Slot Chemistry - Compounds Containing Nitrogen Question 206 English Option 3
D
CH3CH = CH–CH2NH2
2
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider the hydrated ions of Ti2+, V2+, Ti3+, and Sc3+. The correct order of their spin-only magnetic moments is :
A
Sc3+ < Ti3+ < V2+ < Ti2+
B
Sc3+ < Ti3+ < Ti2+ < V2+
C
Ti3+ < Ti2+ < Sc3+ < V2+
D
V2+ < Ti2+ < Ti3+ < Sc3+
3
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the system of linear equations
x + y + z = 5
x + 2y + 2z = 6
x + 3y + $$\lambda $$z = $$\mu $$, ($$\lambda $$, $$\mu $$ $$ \in $$ R), has infinitely many solutions, then the value of $$\lambda $$ + $$\mu $$ is :
A
10
B
9
C
7
D
12
4
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\alpha $$ and $$\beta $$ are the roots of the quadratic equation,
x2 + x sin $$\theta $$ - 2 sin $$\theta $$ = 0, $$\theta \in \left( {0,{\pi \over 2}} \right)$$, then
$${{{\alpha ^{12}} + {\beta ^{12}}} \over {\left( {{\alpha ^{ - 12}} + {\beta ^{ - 12}}} \right).{{\left( {\alpha - \beta } \right)}^{24}}}}$$ is equal to :
A
$${{{2^{12}}} \over {{{\left( {\sin \theta - 8} \right)}^6}}}$$
B
$${{{2^6}} \over {{{\left( {\sin \theta + 4} \right)}^{12}}}}$$
C
$${{{2^{12}}} \over {{{\left( {\sin \theta + 8} \right)}^{12}}}}$$
D
$${{{2^{12}}} \over {{{\left( {\sin \theta - 4} \right)}^{12}}}}$$

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