1
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\sum\limits_{i = 1}^9 {\left( {{x_i} - 5} \right)} = 9$$ and

$$\sum\limits_{i = 1}^9 {{{\left( {{x_i} - 5} \right)}^2}} = 45$$, then the standard deviation of the 9 items
$${x_1},{x_2},.......,{x_9}$$ is
A
3
B
9
C
4
D
2
2
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
A straight line through a fixed point (2, 3) intersects the coordinate axes at distinct points P and Q. If O is the origin and the rectangle OPRQ is completed, then the locus of R is :
A
3x + 2y = 6xy
B
3x + 2y = 6
C
2x + 3y = xy
D
3x + 2y = xy
3
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Let y = y(x) be the solution of the differential equation

$$\sin x{{dy} \over {dx}} + y\cos x = 4x$$, $$x \in \left( {0,\pi } \right)$$.

If $$y\left( {{\pi \over 2}} \right) = 0$$, then $$y\left( {{\pi \over 6}} \right)$$ is equal to :
A
$$ - {4 \over 9}{\pi ^2}$$
B
$${4 \over {9\sqrt 3 }}{\pi ^2}$$
C
$$ - {8 \over {9\sqrt 3 }}{\pi ^2}$$
D
$$ - {8 \over 9}{\pi ^2}$$
4
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Let g(x) = cosx2, f(x) = $$\sqrt x $$ and $$\alpha ,\beta \left( {\alpha < \beta } \right)$$ be the roots of the quadratic equation 18x2 - 9$$\pi $$x + $${\pi ^2}$$ = 0. Then the area (in sq. units) bounded by the curve
y = (gof)(x) and the lines $$x = \alpha $$, $$x = \beta $$ and y = 0 is :
A
$${1 \over 2}\left( {\sqrt 2 - 1} \right)$$
B
$${1 \over 2}\left( {\sqrt 3 - 1} \right)$$
C
$${1 \over 2}\left( {\sqrt 3 + 1} \right)$$
D
$${1 \over 2}\left( {\sqrt 3 - \sqrt 2 } \right)$$

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