1
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
In a collinear collision, a particle with an initial speed v0 strikes a stationary particle of the same mass. If the final total kinetic energy is 50% greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after collision, is :
A
$${{{v_0}} \over {\sqrt 2 }}$$
B
$${{v_0}} \over 4$$
C
$$\sqrt 2 {v_0}$$
D
$${{v_0}} \over 2$$
2
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Unpolarized light of intensity I passes through an ideal polarizer A. Another identical polarizer B is placed behind A. The intensity of light beyond B is found to be I/2. Now another identical polarizer C is placed between A and B. The intensity beyond B is now found to be I/8. The angle between polarizer A and C is :
A
60o
B
30o
C
45o
D
0o
3
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
The mass of a hydrogen molecule is 3.32 $$\times$$ 10-27 kg. If 1023 hydrogen molecules strike, per second, a fixed wall of area 2 cm2 at an angle of 45o to the normal, and rebound elastically with a speed of 103 m/s, then the pressure on the wall is nearly:
A
2.35 $$\times$$ 103 N m-2
B
4.70 $$\times$$ 103 N m-2
C
2.35 $$\times$$ 102 N m-2
D
4.70 $$\times$$ 102 N m-2
4
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B1. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $${{B_2}}$$. The ratio $${{{B_1}} \over {{B_2}}}$$ is:
A
2
B
$$\sqrt 3 $$
C
$$\sqrt 2 $$
D
$$1 \over \sqrt 2 $$

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