1
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
A granite rod of 60 cm length is clamped at its middle point and is set into longitudinal vibrations. The density of granite is 2.7 $$\times$$ 103 kg/m3 and its Young’s modulus is 9.27 $$\times$$ 1010 Pa. What will be the fundamental frequency of the longitudinal vibrations ?
A
7.5 kHz
B
5 kHz
C
2.5 kHz
D
10 kHz
2
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Unpolarized light of intensity I passes through an ideal polarizer A. Another identical polarizer B is placed behind A. The intensity of light beyond B is found to be I/2. Now another identical polarizer C is placed between A and B. The intensity beyond B is now found to be I/8. The angle between polarizer A and C is :
A
60o
B
30o
C
45o
D
0o
3
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
The mass of a hydrogen molecule is 3.32 $$\times$$ 10-27 kg. If 1023 hydrogen molecules strike, per second, a fixed wall of area 2 cm2 at an angle of 45o to the normal, and rebound elastically with a speed of 103 m/s, then the pressure on the wall is nearly:
A
2.35 $$\times$$ 103 N m-2
B
4.70 $$\times$$ 103 N m-2
C
2.35 $$\times$$ 102 N m-2
D
4.70 $$\times$$ 102 N m-2
4
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Two moles of an ideal monatomic gas occupies a volume V at 27oC. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.
A
(a) 195 K (b) 2.7 kJ
B
(a) 189 K (b) 2.7 kJ
C
(a) 195 K (b) –2.7 kJ
D
(a) 189 K (b) – 2.7 kJ
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