1
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Let y = y(x) be the solution of the differential equation

$$\sin x{{dy} \over {dx}} + y\cos x = 4x$$, $$x \in \left( {0,\pi } \right)$$.

If $$y\left( {{\pi \over 2}} \right) = 0$$, then $$y\left( {{\pi \over 6}} \right)$$ is equal to :
A
$$ - {4 \over 9}{\pi ^2}$$
B
$${4 \over {9\sqrt 3 }}{\pi ^2}$$
C
$$ - {8 \over {9\sqrt 3 }}{\pi ^2}$$
D
$$ - {8 \over 9}{\pi ^2}$$
2
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Let g(x) = cosx2, f(x) = $$\sqrt x $$ and $$\alpha ,\beta \left( {\alpha < \beta } \right)$$ be the roots of the quadratic equation 18x2 - 9$$\pi $$x + $${\pi ^2}$$ = 0. Then the area (in sq. units) bounded by the curve
y = (gof)(x) and the lines $$x = \alpha $$, $$x = \beta $$ and y = 0 is :
A
$${1 \over 2}\left( {\sqrt 2 - 1} \right)$$
B
$${1 \over 2}\left( {\sqrt 3 - 1} \right)$$
C
$${1 \over 2}\left( {\sqrt 3 + 1} \right)$$
D
$${1 \over 2}\left( {\sqrt 3 - \sqrt 2 } \right)$$
3
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\left| {\matrix{ {x - 4} & {2x} & {2x} \cr {2x} & {x - 4} & {2x} \cr {2x} & {2x} & {x - 4} \cr } } \right| = \left( {A + Bx} \right){\left( {x - A} \right)^2}$$

then the ordered pair (A, B) is equal to :
A
(4, 5)
B
(-4, -5)
C
(-4, 3)
D
(-4, 5)
4
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on a shelf so that the dictionary is always in the middle. The number of such arrangements is :
A
at least 750 but less than 1000
B
at least 1000
C
less than 500
D
at least 500 but less than 750

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