1
AIEEE 2006
MCQ (Single Correct Answer)
+4
-1
The $$rms$$ value of the electric field of the light coming from the Sun is $$720$$ $$N/C.$$ The average total energy density of the electromagnetic wave is
A
$$4.58 \times {10^{ - 6}}\,J/{m^3}$$
B
$$6.37 \times {10^{ - 9}}\,J/{m^3}$$
C
$$81.35 \times {10^{ - 12}}\,J/{m^3}$$
D
$$3.3 \times {10^{ - 3}}\,J/{m^3}$$
2
AIEEE 2006
MCQ (Single Correct Answer)
+4
-1
When $${}_3L{i^7}$$ nuclei are bombarded by protons, and the resultant nuclei are $${}_4B{e^8}$$, the emitted particles will be
A
alpha particles
B
beta particles
C
gamma photons
D
neutrons
3
AIEEE 2006
MCQ (Single Correct Answer)
+4
-1
An alpha nucleus of energy $${1 \over 2}m{v^2}$$ bombards a heavy nuclear target of charge $$Ze$$. Then the distance of closest approach for the alpha nucleus will be proportional to
A
$${v^2}$$
B
$${1 \over m}$$
C
$${1 \over {{v^2}}}$$
D
$${1 \over {Ze}}$$
4
AIEEE 2006
MCQ (Single Correct Answer)
+4
-1
If the binding energy per nucleon in $${}_3^7Li$$ and $${}_2^4He$$ nuclei are $$5.60$$ $$MeV$$ and $$7.06$$ $$MeV$$ respectively, then in the reaction $$$p + {}_3^7Li \to 2\,{}_2^4He$$$
energy of proton must be
A
$$28.24$$ $$MeV$$
B
$$17.28$$ $$MeV$$
C
$$1.46$$ $$MeV$$
D
$$39.2$$ $$MeV$$

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