JEE Main 2021 (Online) 25th July Morning Shift | Dual Nature of Radiation Question 86 | Physics

What should be the order of arrangement of de-Broglie wavelength of electron ($$\lambda$$_e), an $$\alpha$$-particle ($$\lambda$$_a) and proton ($$\lambda$$_p) given that all have the same kinetic energy?

$$\lambda$$_e = $$\lambda$$_p = $$\lambda$$_$$\alpha$$

$$\lambda$$_e < $$\lambda$$_p < $$\lambda$$_$$\alpha$$

$$\lambda$$_e > $$\lambda$$_p > $$\lambda$$_$$\alpha$$

$$\lambda$$_e = $$\lambda$$_p > $$\lambda$$_$$\alpha$$

JEE Main 2021 (Online) 25th July Morning Shift

MCQ (Single Correct Answer)

-1

A particle of mass 4M at rest disintegrates into two particles of mass M and 3M respectively having non zero velocities. The ratio of de-Broglie wavelength of particle of mass M to that of mass 3M will be :

1 : 3

3 : 1

1 : $$\sqrt 3 $$

1 : 1

JEE Main 2021 (Online) 22th July Evening Shift

MCQ (Single Correct Answer)

-1

An electron of mass m_e and a proton of mass m_p are accelerated through the same potential difference. The ratio of the de-Broglie wavelength associated with the electron to that with the proton is

$${{{m_e}} \over {{m_p}}}$$

$${{{m_p}} \over {{m_e}}}$$

$$\sqrt {{{{m_p}} \over {{m_e}}}} $$

JEE Main 2021 (Online) 20th July Evening Shift

MCQ (Single Correct Answer)

-1

An electron having de-Broglie wavelength $$\lambda$$ is incident on a target in a X-ray tube. Cut-off wavelength of emitted X-ray is :

$${{2{m^2}{c^2}{\lambda ^2}} \over {{h^2}}}$$

$${{2mc{\lambda ^2}} \over h}$$

$${{hc} \over {mc}}$$

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