JEE Main 2022 (Online) 28th June Morning Shift | Dual Nature of Radiation Question 101 | Physics

The de Broglie wavelengths for an electron and a photon are $$\lambda$$_e and $$\lambda$$_p respectively. For the same kinetic energy of electron and photon, which of the following presents the correct relation between the de Broglie wavelengths of two ?

$${\lambda _p} \propto \lambda _e^2$$

$${\lambda _p} \propto {\lambda _e}$$

$${\lambda _p} \propto \sqrt {{\lambda _e}} $$

$${\lambda _p} \propto \sqrt {{1 \over {{\lambda _e}}}} $$

JEE Main 2022 (Online) 27th June Morning Shift

MCQ (Single Correct Answer)

-1

An $$\alpha$$ particle and a carbon 12 atom has same kinetic energy K. The ratio of their de-Broglie wavelengths $$({\lambda _\alpha }:{\lambda _{C12}})$$ is :

$$1:\sqrt 3 $$

$$\sqrt 3 :1$$

$$3:1$$

$$2:\sqrt 3 $$

JEE Main 2022 (Online) 26th June Evening Shift

MCQ (Single Correct Answer)

-1

A metal surface is illuminated by a radiation of wavelength 4500 $$\mathop A\limits^o $$. The ejected photo-electron enters a constant magnetic field of 2 mT making an angle of 90$$^\circ$$ with the magnetic field. If it starts revolving in a circular path of radius 2 mm, the work function of the metal is approximately :

1.36 eV

1.69 eV

2.78 eV

2.23 eV

JEE Main 2022 (Online) 26th June Morning Shift

MCQ (Single Correct Answer)

-1

An electron with speed v and a photon with speed c have the same de-Broglie wavelength. If the kinetic energy and momentum of electron are E_e and p_e and that of photon are E_ph and p_ph respectively. Which of the following is correct?

$${{{E_e}} \over {{E_{ph}}}} = {{2c} \over v}$$

$${{{E_e}} \over {{E_{ph}}}} = {v \over {2c}}$$

$${{{p_e}} \over {{p_{ph}}}} = {{2c} \over v}$$

$${{{p_e}} \over {{p_{ph}}}} = {v \over {2c}}$$

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