JEE Main 2024 (Online) 29th January Evening Shift | Dual Nature of Radiation Question 21 | Physics

Two sources of light emit with a power of $$200 \mathrm{~W}$$. The ratio of number of photons of visible light emitted by each source having wavelengths $$300 \mathrm{~nm}$$ and $$500 \mathrm{~nm}$$ respectively, will be :

$$5: 3$$

$$3: 5$$

$$1: 5$$

$$1: 3$$

JEE Main 2024 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

The de-Broglie wavelength of an electron is the same as that of a photon. If velocity of electron is $$25 \%$$ of the velocity of light, then the ratio of K.E. of electron and K.E. of photon will be:

$$\frac{1}{4}$$

$$\frac{8}{1}$$

$$\frac{1}{8}$$

$$\frac{1}{1}$$

JEE Main 2024 (Online) 27th January Evening Shift

MCQ (Single Correct Answer)

-1

The threshold frequency of a metal with work function $$6.63 \mathrm{~eV}$$ is :

$$16 \times 10^{15} \mathrm{~Hz}$$

$$16 \times 10^{12} \mathrm{~Hz}$$

$$1.6 \times 10^{15} \mathrm{~Hz}$$

$$1.6 \times 10^{12} \mathrm{~Hz}$$

JEE Main 2023 (Online) 15th April Morning Shift

MCQ (Single Correct Answer)

-1

The de Broglie wavelength of an electron having kinetic energy $\mathrm{E}$ is $\lambda$. If the kinetic energy of electron becomes $\frac{E}{4}$, then its de-Broglie wavelength will be :

$\sqrt{2} \lambda$

$2 \lambda$

$\frac{\lambda}{2}$

$\frac{\lambda}{\sqrt{2}}$

PREVIOUS NEXT

Questions Asked from Dual Nature of Radiation (MCQ (Single Correct Answer))

Number in Brackets after Paper Indicates No. of Questions