JEE Main 2020 (Online) 6th September Morning Slot | Dual Nature of Radiation Question 65 | Physics

JEE Main 2020 (Online) 6th September Morning Slot

MCQ (Single Correct Answer)

-1

An electron, a doubly ionized helium ion (He⁺⁺) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths $$\lambda $$_e, $$\lambda $$_He⁺⁺ and $$\lambda $$_p is :

$$\lambda $$_e > $$\lambda $$_He⁺⁺ > $$\lambda $$_p

$$\lambda $$_e < $$\lambda $$_p < $$\lambda $$_He⁺⁺

$$\lambda $$_e > $$\lambda $$_p > $$\lambda $$_He⁺⁺

$$\lambda $$_e < $$\lambda $$_He⁺⁺ = $$\lambda $$_p

JEE Main 2020 (Online) 6th September Morning Slot

MCQ (Single Correct Answer)

-1

You are given that Mass of $${}_3^7Li$$ = 7.0160u,
Mass of $${}_2^4He$$ = 4.0026u
and Mass of $${}_1^1H$$ = 1.0079u.
When 20 g of $${}_3^7Li$$ is converted into $${}_2^4He$$ by proton capture, the energy liberated, (in kWh), is :
[Mass of nucleon = 1 GeV/c²]

6.82 $$ \times $$ 10⁵

4.5 $$ \times $$ 10⁵

8 $$ \times $$ 10⁶

1.33 $$ \times $$ 10⁶

JEE Main 2020 (Online) 5th September Evening Slot

MCQ (Single Correct Answer)

-1

The correct match between the entries in column I and column II are :

I	II
Radiation	Wavelength
(a) Microwave	(i) 100 m
(b) Gamma rays	(ii) 10^–15 m
(c) A.M. radio waves	(iii) 10^–10 m
(d) X-rays	(iv) 10^–3 m

(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)

(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)

(a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

JEE Main 2020 (Online) 4th September Evening Slot

MCQ (Single Correct Answer)

-1

Find the Binding energy per neucleon for $${}_{50}^{120}Sn$$. Mass of proton m_p = 1.00783 U, mass of neutron m_n = 1.00867 U and mass of tin nucleus m_Sn = 119.902199 U. (take 1U = 931 MeV)

9.0 MeV

8.5 MeV

8.0 MeV

7.5 MeV

PREVIOUS NEXT