1
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Assuming the nitrogen molecule is moving with r.m.s. velocity at 400 K, the de-Broglie wavelength of nitrogen molecule is close to :
(Given : nitrogen molecule weight : 4.64 $$ \times $$ 10–26 kg,
Boltzman constant: 1.38 $$ \times $$ 10–23 J/K,
Planck constant : 6.63 $$ \times $$ 10–34 J.s)
A
0.44 $$\mathop A\limits^o $$
B
0.34 $$\mathop A\limits^o $$
C
0.20 $$\mathop A\limits^o $$
D
0.24 $$\mathop A\limits^o $$
2
JEE Main 2020 (Online) 6th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An electron, a doubly ionized helium ion (He++) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths $$\lambda $$e, $$\lambda $$He++ and $$\lambda $$p is :
A
$$\lambda $$e > $$\lambda $$He++ > $$\lambda $$p
B
$$\lambda $$e < $$\lambda $$p < $$\lambda $$He++
C
$$\lambda $$e > $$\lambda $$p > $$\lambda $$He++
D
$$\lambda $$e < $$\lambda $$He++ = $$\lambda $$p
3
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased : JEE Main 2020 (Online) 4th September Evening Slot Physics - Dual Nature of Radiation Question 111 English
A
Slope of the straight line get more steep
B
Graph does not change
C
Straight line shifts to left
D
Straight line shifts to right
4
JEE Main 2020 (Online) 4th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Particle A of mass mA = $${m \over 2}$$ moving along the x-axis with velocity v0 collides elastically with another particle B at rest having mass mB = $${m \over 3}$$. If both particles move along the x-axis after the collision, the change $$\Delta $$$$\lambda $$ in de-Broglie wavlength of particle A, in terms of its de-Broglie wavelength ($$\lambda $$0) before collision is :
A
$$\Delta $$$$\lambda $$ = $${5 \over 2}{\lambda _0}$$
B
$$\Delta $$$$\lambda $$ = $${3 \over 2}{\lambda _0}$$
C
$$\Delta $$$$\lambda $$ = 2$$\lambda $$0
D
$$\Delta $$$$\lambda $$ = 4$$\lambda $$0
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