1
JEE Main 2022 (Online) 25th July Morning Shift
+4
-1 A metal exposed to light of wavelength $$800 \mathrm{~nm}$$ and and emits photoelectrons with a certain kinetic energy. The maximum kinetic energy of photo-electron doubles when light of wavelength $$500 \mathrm{~nm}$$ is used. The workfunction of the metal is : (Take hc $$=1230 \,\mathrm{eV}-\mathrm{nm}$$ ).

A
1.537 eV
B
2.46 eV
C
0.615 eV
D
1.23 eV
2
JEE Main 2022 (Online) 30th June Morning Shift
+4
-1

A source of monochromatic light liberates 9 $$\times$$ 1020 photon per second with wavelength 600 nm when operated at 400 W. The number of photons emitted per second with wavelength of 800 nm by the source of monochromatic light operating at same power will be :

A
12 $$\times$$ 1020
B
6 $$\times$$ 1020
C
9 $$\times$$ 1020
D
24 $$\times$$ 1020
3
JEE Main 2022 (Online) 29th June Evening Shift
+4
-1 The electric field at a point associated with a light wave is given by

E = 200 [sin (6 $$\times$$ 1015)t + sin (9 $$\times$$ 1015)t] Vm$$-$$1

Given : h = 4.14 $$\times$$ 10$$-$$15 eVs

If this light falls on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be

A
1.90 eV
B
3.27 eV
C
3.60 eV
D
3.42 eV
4
JEE Main 2022 (Online) 29th June Morning Shift
+4
-1 Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R :

Assertion A : The photoelectric effect does not takes place, if the energy of the incident radiation is less than the work function of a metal.

Reason R : Kinetic energy of the photoelectrons is zero, if the energy of the incident radiation is equal to the work function of a metal.

In the light of the above statements, choose the most appropriate answer from the options given below.

A
Both A and R are correct and R is the correct explanation of A.
B
Both A and R are correct but R is not the correct explanation of A.
C
A is correct but R is not correct.
D
A is not correct but R is correct.
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