JEE Main 2021 (Online) 17th March Evening Shift | Dual Nature of Radiation Question 115 | Physics

Two identical photocathodes receive the light of frequencies f₁ and f₂ respectively. If the velocities of the photo-electrons coming out are v₁ and v₂ respectively, then

$${v_1} - {v_2} = {\left[ {{{2h} \over m}({f_1} - {f_2})} \right]^{{1 \over 2}}}$$

$$v_1^2 + v_2^2 = {{2h} \over m}[{f_1} + {f_2}]$$

$${v_1} + {v_2} = {\left[ {{{2h} \over m}({f_1} + {f_2})} \right]^{{1 \over 2}}}$$

$$v_1^2 - v_2^2 = {{2h} \over m}[{f_1} - {f_2}]$$

JEE Main 2021 (Online) 17th March Morning Shift

MCQ (Single Correct Answer)

-1

An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is : (c being the velocity of light)

$${1 \over c}{\left( {{{2m} \over E}} \right)^{1/2}}$$

$${1 \over c}{\left( {{E \over {2m}}} \right)^{1/2}}$$

$${\left( {{E \over {2m}}} \right)^{1/2}}$$

$$c{(2mE)^{1/2}}$$

JEE Main 2021 (Online) 16th March Evening Shift

MCQ (Single Correct Answer)

-1

The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of 100 V. What should nearly be the ratio of their wavelengths? (m_p = 1.00727u m_e = 0.00055u)

41.4 : 1

(1860)² : 1

1860 : 1

43 : 1

JEE Main 2021 (Online) 16th March Morning Shift

MCQ (Single Correct Answer)

-1

The stopping potential in the context of photoelectric effect depends on the following property of incident electromagnetic radiation :

Phase

Frequency

Amnplitude

Intensity