AIEEE 2003 | Dual Nature of Radiation Question 170 | Physics

Two identical photo-cathodes receive light of frequencies $${f_1}$$ and $${f_2}$$. If the velocities of the photo electrons (of mass $$m$$ ) coming out are respectively $${v_1}$$ and $${v_2},$$ then

$$v_1^2 - v_2^2 = {{2h} \over m}\left( {{f_1} - {f_2}} \right)$$

$${v_1} + {v_2} = {\left[ {{{2h} \over m}\left( {{f_1} + {f_2}} \right)} \right]^{1/2}}$$

$$v_1^2 + v_2^2 = {{2h} \over m}\left( {{f_1} + {f_2}} \right)$$

$${v_1} - {v_2} = {\left[ {{{2h} \over m}\left( {{f_1} - {f_2}} \right)} \right]^{1/2}}$$

AIEEE 2002

MCQ (Single Correct Answer)

-1

Sodium and copper have work functions $$2.3$$ $$eV$$ and $$4.5$$ $$eV$$ respectively. Then the ratio of the wavelengths is nearest to

$$1:2$$

$$4:1$$

$$2:1$$

$$1:4$$

AIEEE 2002

MCQ (Single Correct Answer)

-1

Formation of covalent bonds in compounds exhibits

wave nature of electron

particle nature of electron

both wave and particle nature of electron

none of these

Questions Asked from Dual Nature of Radiation (MCQ (Single Correct Answer))

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