1
JEE Main 2021 (Online) 26th February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
If two similar springs each of spring constant K1 are joined in series, the new spring constant and time period would be changed by a factor :
A
$${1 \over 2},2\sqrt 2 $$
B
$${1 \over 4},2\sqrt 2 $$
C
$${1 \over 2},\sqrt 2 $$
D
$${1 \over 4},\sqrt 2 $$
2
JEE Main 2021 (Online) 25th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Y = A sin($$\omega$$t + $$\phi$$0) is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is $$Y = {A \over 2}$$ and it is moving along negative x-direction. Then the initial phase angle $$\phi$$0 will be:
A
$${{5\pi } \over 6}$$
B
$${{\pi } \over 3}$$
C
$${{2\pi } \over 3}$$
D
$${{\pi } \over 6}$$
3
JEE Main 2021 (Online) 25th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Two identical springs of spring constant '2k' are attached to a block of mass m and to fixed support (see figure). When the mass is displaced from equilibrium position on either side, it executes simple harmonic motion. The time period of oscillations of this system is :

JEE Main 2021 (Online) 25th February Evening Shift Physics - Simple Harmonic Motion Question 89 English
A
$$2\pi \sqrt {{m \over k}} $$
B
$$\pi \sqrt {{m \over k}} $$
C
$$2\pi \sqrt {{m \over {2k}}} $$
D
$$\pi \sqrt {{m \over {2k}}} $$
4
JEE Main 2021 (Online) 25th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
The point A moves with a uniform speed along the circumference of a circle of radius 0.36 m and covers 30$$^\circ$$ in 0.1 s. The perpendicular projection 'P' from 'A' on the diameter MN represents the simple harmonic motion of 'P'. The restoration force per unit mass when P touches M will be :

JEE Main 2021 (Online) 25th February Evening Shift Physics - Simple Harmonic Motion Question 88 English
A
9.87 N
B
0.49 N
C
50 N
D
100 N
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