JEE Main 2021 (Online) 24th February Evening Shift | Dual Nature of Radiation Question 126 | Physics

Given below are two statements :

Statement I : Two photons having equal linear momenta have equal wavelengths.

Statement II : If the wavelength of photon is decreased, then the momentum and energy of a photon will also decrease.

In the light of the above statements, choose the correct answer from the options given below.

Statement I is false but Statement II is true

Both Statement I and Statement II are false

Both Statement I and Statement II are true

Statement I is true but Statement II is false

JEE Main 2020 (Online) 6th September Evening Slot

MCQ (Single Correct Answer)

-1

Assuming the nitrogen molecule is moving with r.m.s. velocity at 400 K, the de-Broglie wavelength of nitrogen molecule is close to :
(Given : nitrogen molecule weight : 4.64 $$ \times $$ 10^–26 kg,
Boltzman constant: 1.38 $$ \times $$ 10^–23 J/K,
Planck constant : 6.63 $$ \times $$ 10^–34 J.s)

0.44 $$\mathop A\limits^o $$

0.34 $$\mathop A\limits^o $$

0.20 $$\mathop A\limits^o $$

0.24 $$\mathop A\limits^o $$

JEE Main 2020 (Online) 6th September Morning Slot

MCQ (Single Correct Answer)

-1

An electron, a doubly ionized helium ion (He⁺⁺) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths $$\lambda $$_e, $$\lambda $$_He⁺⁺ and $$\lambda $$_p is :

$$\lambda $$_e > $$\lambda $$_He⁺⁺ > $$\lambda $$_p

$$\lambda $$_e < $$\lambda $$_p < $$\lambda $$_He⁺⁺

$$\lambda $$_e > $$\lambda $$_p > $$\lambda $$_He⁺⁺

$$\lambda $$_e < $$\lambda $$_He⁺⁺ = $$\lambda $$_p

PREVIOUS NEXT

Questions Asked from Dual Nature of Radiation (MCQ (Single Correct Answer))

Number in Brackets after Paper Indicates No. of Questions