AIEEE 2005 | Simple Harmonic Motion Question 168 | Physics

The bob of a simple pendulum is a spherical hollow ball filled with water. A plugged hole near the bottom of the oscillating bob gets suddenly unplugged. During observation, till water is coming out, the time period of oscillation would

first decrease and then increase to the original value

first increase and then decrease to the original value

increase towards a saturation value

remain unchanged

AIEEE 2004

MCQ (Single Correct Answer)

-1

A particle of mass $$m$$ is attached to a spring (of spring constant $$k$$) and has a natural angular frequency $${\omega _0}.$$ An external force $$F(t)$$ proportional to $$\cos \,\omega t\left( {\omega \ne {\omega _0}} \right)$$ is applied to the oscillator. The time displacement of the oscillator will be proportional to

$${1 \over {m\left( {\omega _0^2 + {\omega ^2}} \right)}}$$

$${1 \over {m\left( {\omega _0^2 - {\omega ^2}} \right)}}$$

$${m \over {\omega _0^2 - {\omega ^2}}}$$

$${m \over {\omega _0^2 + {\omega ^2}}}$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

Out of Syllabus

In forced oscillation of a particle the amplitude is maximum for a frequency $${\omega _1}$$ of the force while the energy is maximum for a frequency $${\omega _2}$$ of the force; then

$${\omega _1} < {\omega _2}$$ when damping is small and $${\omega _1} > {\omega _2}$$ when damping is large

$${\omega _1} > {\omega _2}$$

$${\omega _1} = {\omega _2}$$

$${\omega _1} < {\omega _2}$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

The bob of a simple pendulum executes simple harmonic motion in water with a period $$t,$$ while the period of oscillation of the bob is $${t_0}$$ in air. Neglecting frictional force of water and given that the density of the bob is $$\left( {4/3} \right) \times 1000\,\,kg/{m^3}.$$ What relationship between $$t$$ and $${t_0}$$ is true

$$t = 2{t_0}$$

$$t = {t_0}/2$$

$$t = {t_0}$$

$$t = 4{t_0}$$

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