1
JEE Main 2023 (Online) 29th January Evening Shift
+4
-1

Which of the following relations are correct?

(A) $$\mathrm{\Delta U=q+p\Delta V}$$

(B) $$\mathrm{\Delta G=\Delta H-T\Delta S}$$

(C) $$\Delta \mathrm{S}=\frac{q_{rev}}{T}$$

(D) $$\mathrm{\Delta H=\Delta U-\Delta nRT}$$

Choose the most appropriate answer from the options given below :

A
A and B only
B
B and C only
C
C and D only
D
B and D only
2
JEE Main 2022 (Online) 29th July Evening Shift
+4
-1

\begin{aligned} &\mathrm{C}(\mathrm{s})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{CO}_{2}(\mathrm{~g})+400 \mathrm{~kJ} \\ &\mathrm{C}(\mathrm{s})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{CO}(\mathrm{g})+100 \mathrm{~kJ} \end{aligned}

When coal of purity 60% is allowed to burn in presence of insufficient oxygen, 60% of carbon is converted into 'CO' and the remaining is converted into '$$\mathrm{CO}_{2}$$'. The heat generated when $$0.6 \mathrm{~kg}$$ of coal is burnt is _________.

A
1600 kJ
B
3200 kJ
C
4400 kJ
D
6600 kJ
3
JEE Main 2022 (Online) 28th July Evening Shift
+4
-1

Given below are two statements: One is labelled as Assertion $$\mathbf{A}$$ and the other is labelled as Reason $$\mathbf{R}$$

Assertion A: The reduction of a metal oxide is easier if the metal formed is in liquid state than solid state.

Reason $$\mathbf{R}$$ : The value of $$\Delta G ^\Theta$$ becomes more on negative side as entropy is higher in liquid state than solid state.

In the light of the above statements, choose the most appropriate answer from the options given below

A
Both A and R are correct and R is the correct explanation of A
B
Both A and R are correct but R is NOT the correct explanation of A
C
A is correct but R is not correct
D
A is not correct but R is correct
4
JEE Main 2022 (Online) 28th July Morning Shift
+4
-1

Which of the following relation is not correct?

A
$$\Delta \mathrm{H}=\Delta \mathrm{U}-\mathrm{P} \Delta \mathrm{V}$$
B
$$\Delta \mathrm{U}=\mathrm{q}+\mathrm{W}$$
C
$$\Delta \mathrm{S}_{\text {sys }}+\Delta \mathrm{S}_{\text {surr }} \geqslant 0$$
D
$$\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}$$
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