JEE Main 2019 (Online) 9th April Morning Slot | Thermodynamics Question 109 | Chemistry

5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If C_V = 28 JK^–1mol^–1, calculate $$\Delta $$U and $$\Delta $$pV for this process. (R = 8.0 JK^–1 mol^–1]

$$\Delta $$U = 14 kJ; $$\Delta $$(pV) = 4 kJ

$$\Delta $$U = 2.8 kJ; $$\Delta $$(pV) = 0.8 kJ

$$\Delta $$U = 14 kJ; $$\Delta $$(pV) = 18 kJ

$$\Delta $$U = 14 kJ; $$\Delta $$(pV) = 0.8 kJ

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

For silver, C_p(J K^–1 mol^–1) = 23 +0.01 T. If the temperature (T) of 3 moles of silver is raised from 300 K to 1000 K at 1 atm pressure, the value of $$\Delta H$$ will be close to :

62 KJ

16 KJ

13 KJ

21 KJ

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

Which one of the following equations does not correctly represent the first law of thermodynamics for the given processes involving an ideal gas? (Assume non-expansion work is zero)

Adiabatic process : $$\Delta $$U= – w

Cyclic process : q = –w

Isochoric process : $$\Delta $$U= q

Isothermal process : q = – w

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