1
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV = 28 JK–1mol–1, calculate $$\Delta $$U and $$\Delta $$pV for this process. (R = 8.0 JK–1 mol–1]
A
$$\Delta $$U = 14 kJ; $$\Delta $$(pV) = 4 kJ
B
$$\Delta $$U = 2.8 kJ; $$\Delta $$(pV) = 0.8 kJ
C
$$\Delta $$U = 14 kJ; $$\Delta $$(pV) = 18 kJ
D
$$\Delta $$U = 14 kJ; $$\Delta $$(pV) = 0.8 kJ
2
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For silver, Cp(J K–1 mol–1) = 23 +0.01 T. If the temperature (T) of 3 moles of silver is raised from 300 K to 1000 K at 1 atm pressure, the value of $$\Delta H$$ will be close to :
A
62 KJ
B
16 KJ
C
13 KJ
D
21 KJ
3
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Which one of the following equations does not correctly represent the first law of thermodynamics for the given processes involving an ideal gas? (Assume non-expansion work is zero)
A
Adiabatic process : $$\Delta $$U= – w
B
Cyclic process : q = –w
C
Isochoric process : $$\Delta $$U= q
D
Isothermal process : q = – w
4
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The combination of plots which does not represent isothermal expansion of an ideal gas is –

JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Thermodynamics Question 119 English
A
A and D
B
B and D
C
B and C
D
A and C
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