The solution from the following with highest depression in freezing point/lowest freezing point is

What happens to freezing point of benzene when small quantity of napthalene is added to benzene?

A solution of two miscible liquids showing negative deviation from Raoult's law will have :

What weight of glucose must be dissolved in $$100 \mathrm{~g}$$ of water to lower the vapour pressure by $$0.20 \mathrm{~mm} ~\mathrm{Hg}$$ ?

(Assume dilute solution is being formed)

Given : Vapour pressure of pure water is $$54.2 \mathrm{~mm} ~\mathrm{Hg}$$ at room temperature. Molar mass of glucose is $$180 \mathrm{~g} \mathrm{~mol}^{-1}$$