1
JEE Main 2025 (Online) 22nd January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Arrange the following solutions in order of their increasing boiling points.

(i) $10^{-4} \mathrm{M} \mathrm{NaCl}$

(ii) $10^{-4} \mathrm{M}$ Urea

(iii) $10^{-3} \mathrm{M} \mathrm{NaCl}$

(iv) $10^{-2} \mathrm{M} \mathrm{NaCl}$

A
$($ i $)<($ ii $)<($ iii $)<($ iv $)$
B
(ii) $<($ i $)<($ iii $)<($ iv $)$
C
(iv) $<($ iii $)<($ i $)<($ ii $)$
D
(ii) $<$ (i) $\equiv$ (iii) $<$ (iv)
2
JEE Main 2024 (Online) 9th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$$0.05 \mathrm{M} \mathrm{~CuSO}_4$$ when treated with $$0.01 \mathrm{M} \mathrm{~K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ gives green colour solution of $$\mathrm{Cu}_2 \mathrm{Cr}_2 \mathrm{O}_7$$. The two solutions are separated as shown below : [SPM : Semi Permeable Membrane]

JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Solutions Question 29 English

Due to osmosis :

A
Molarity of $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ solution is lowered.
B
Green colour formation observed on side Y.
C
Molarity of $$\mathrm{CuSO}_4$$ solution is lowered.
D
Green colour formation observed on side X.
3
JEE Main 2024 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
We have three aqueous solutions of $\mathrm{NaCl}$ labelled as ' $\mathrm{A}$ ', ' $\mathrm{B}$ ' and ' $\mathrm{C}$ ' with concentration $0.1 \mathrm{M}$, $0.01 \mathrm{M}$ and $0.001 \mathrm{M}$, respectively. The value of van 't Hoff factor(i) for these solutions will be in the order :
A
$\mathrm{i}_{\mathrm{A}}<\mathrm{i}_{\mathrm{C}}<\mathrm{i}_{\mathrm{B}}$
B
$\mathrm{i}_{\mathrm{A}}<\mathrm{i}_{\mathrm{B}}<\mathrm{i}_{\mathrm{C}}$
C
$\mathrm{i}_{\mathrm{A}}>\mathrm{i}_{\mathrm{B}}>\mathrm{i}_{\mathrm{C}}$
D
$\mathrm{i}_{\mathrm{A}}=\mathrm{i}_{\mathrm{B}}=\mathrm{i}_{\mathrm{C}}$
4
JEE Main 2024 (Online) 31st January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Identify the mixture that shows positive deviations from Raoult's Law

A
$$\left(\mathrm{CH}_3\right)_2 \mathrm{CO}+\mathrm{CS}_2$$
B
$$\left(\mathrm{CH}_3\right)_2 \mathrm{CO}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2$$
C
$$\mathrm{CHCl}_3+\mathrm{C}_6 \mathrm{H}_6$$
D
$$\mathrm{CHCl}_3+\left(\mathrm{CH}_3\right)_2 \mathrm{CO}$$
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