1
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Liquid 'M' and liquid 'N' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are 450 and 700 mmHg, respectively, at the same temperature. Then correct statement is:
(xM = Mole fraction of 'M' in solution ;
xN = Mole fraction of 'N' in solution ;
yM = Mole fraction of 'M' in vapour phase ;
yN = Mole fraction of 'N' in vapour phase)
A
$${{{x_M}} \over {{x_N}}} < {{{y_N}} \over {{y_N}}}$$
B
(xM – yM) < (xN – yN)
C
$${{{x_M}} \over {{x_N}}} = {{{y_N}} \over {{y_N}}}$$
D
$${{{x_M}} \over {{x_N}}} > {{{y_M}} \over {{y_N}}}$$
2
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the solution of the gases w, x, y and z in water at 298K, the Henrys law constants (KH) are 0.5, 2, 35 and 40 kbar, respectively. The correct plot for the given data is :-
A
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 107 English Option 1
B
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 107 English Option 2
C
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 107 English Option 3
D
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 107 English Option 4
3
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The vapour pressures of pure liquids A and B are 400 and 600 mmHg, respectively at 298 K on mixing the two liquids, the sum of their initial volume is equal ot the volume of the final mixture. The mole fraction of liquid B is 0.5 in the mixture, The vapour pressure of the final solution, the mole fractions of components A and B in vapour phase, respectively are :
A
500 mmHg. 0.5,0.5
B
500 mmHg, 0.4, 0.6
C
450 mmHg, 0.4,0.6
D
450 mmHg.0.5,0.5
4
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Molecules of benzoic acid (C6H5COOH) dimerise in benzene. 'w' g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2K. If the percentage association of the acid to form dimmer in the solution is 80, then w is – (Its given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)
A
1.5 g
B
1.8 g
C
1.0 g
D
2.4 g
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