JEE Main 2024 (Online) 9th April Morning Shift | Solutions Question 24 | Chemistry

JEE Main 2024 (Online) 9th April Morning Shift

MCQ (Single Correct Answer)

-1

$$0.05 \mathrm{M} \mathrm{~CuSO}_4$$ when treated with $$0.01 \mathrm{M} \mathrm{~K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ gives green colour solution of $$\mathrm{Cu}_2 \mathrm{Cr}_2 \mathrm{O}_7$$. The two solutions are separated as shown below : [SPM : Semi Permeable Membrane]

JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Solutions Question 29 English

Due to osmosis :

Molarity of $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ solution is lowered.

Green colour formation observed on side Y.

Molarity of $$\mathrm{CuSO}_4$$ solution is lowered.

Green colour formation observed on side X.

JEE Main 2024 (Online) 1st February Morning Shift

MCQ (Single Correct Answer)

-1

We have three aqueous solutions of $\mathrm{NaCl}$ labelled as ' $\mathrm{A}$ ', ' $\mathrm{B}$ ' and ' $\mathrm{C}$ ' with concentration $0.1 \mathrm{M}$, $0.01 \mathrm{M}$ and $0.001 \mathrm{M}$, respectively. The value of van 't Hoff factor(i) for these solutions will be in the order :

$\mathrm{i}_{\mathrm{A}}<\mathrm{i}_{\mathrm{C}}<\mathrm{i}_{\mathrm{B}}$

$\mathrm{i}_{\mathrm{A}}<\mathrm{i}_{\mathrm{B}}<\mathrm{i}_{\mathrm{C}}$

$\mathrm{i}_{\mathrm{A}}>\mathrm{i}_{\mathrm{B}}>\mathrm{i}_{\mathrm{C}}$

$\mathrm{i}_{\mathrm{A}}=\mathrm{i}_{\mathrm{B}}=\mathrm{i}_{\mathrm{C}}$

JEE Main 2024 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

Identify the mixture that shows positive deviations from Raoult's Law

$$\left(\mathrm{CH}_3\right)_2 \mathrm{CO}+\mathrm{CS}_2$$

$$\left(\mathrm{CH}_3\right)_2 \mathrm{CO}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2$$

$$\mathrm{CHCl}_3+\mathrm{C}_6 \mathrm{H}_6$$

$$\mathrm{CHCl}_3+\left(\mathrm{CH}_3\right)_2 \mathrm{CO}$$

JEE Main 2024 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

The solution from the following with highest depression in freezing point/lowest freezing point is

$$180 \mathrm{~g}$$ of acetic acid dissolved in benzene

$$180 \mathrm{~g}$$ of acetic acid dissolved in water

$$180 \mathrm{~g}$$ of benzoic acid dissolved in benzene

$$180 \mathrm{~g}$$ of glucose dissolved in water

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