1
JEE Main 2020 (Online) 6th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the reaction

Fe2N(s) + $${3 \over 2}$$H2(g) ⇌ 2Fe(s) + NH3(g)
A
KC = Kp(RT)1/2
B
KC = Kp(RT)-1/2
C
KC = Kp(RT)
D
KC = Kp(RT)3/2
2
JEE Main 2020 (Online) 6th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The variation of equilibrium constant with temperature is given below :

Temperature Equilibrium Constant
T1 = 25oC K1 = 10
T2 = 100oC K2 = 100

The values of $$\Delta $$Ho, $$\Delta $$Go at
T1 and $$\Delta $$Go at T2 (in kJ mol–1) respectively, are close to :
[Use R = 8.314 J K–1 mol–1]
A
28.4, –5.71 and –14.29
B
0.64, –7.14 and –5.71
C
28.4, –7.14 and –5.71
D
0.64, –5.71 and –14.29
3
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider the following reaction:

N2O4(g) ⇌ 2NO2(g); $$\Delta $$Ho = +58 kJ

For each of the following cases (a, b), the direction in which the equilibrium shifts is :
(a) Temperature is decreased.
(b) Pressure is increased by adding N2 at constant T.
A
(a) towards reactant, (b) towards product
B
(a) towards reactant, (b) no change
C
(a) towards product, (b) towards reactant
D
(a) towards product, (b) no change
4
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the equilibrium constant for
A ⇌ B + C is $$K_{eq}^{(1)}$$ and that of
B + C ⇌ P is $$K_{eq}^{(2)}$$, the equilibrium
constant for A ⇌ P is :
A
$${{K_{eq}^{(1)}} \over {K_{eq}^{(2)}}}$$
B
$${K_{eq}^{(1)}}$$ + $${K_{eq}^{(2)}}$$
C
$${K_{eq}^{(2)}}$$ - $${K_{eq}^{(1)}}$$
D
$${K_{eq}^{(1)}}$$ $${K_{eq}^{(2)}}$$
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