This chapter is currently out of syllabus
1
JEE Main 2019 (Online) 10th January Morning Slot
+4
-1
Out of Syllabus
Consider a triangular plot ABC with sides AB = 7m, BC = 5m and CA = 6m. A vertical lamp-post at the mid point D of AC subtends an angle 30o at B. The height (in m) of the lamp-post is -
A
$$2\sqrt {21}$$
B
$${3 \over 2}\sqrt {21}$$
C
$$7\sqrt {3}$$
D
$${2 \over 3}\sqrt {21}$$
2
JEE Main 2018 (Online) 16th April Morning Slot
+4
-1
Out of Syllabus
A man on the top of a vertical tower observes a car moving at a uniform speed towards the tower on a horizontal road. If it takes 18 min. for the angle of depression of the car to change from 30o to 45o ; then after this, the time taken (in min.) by the car to reach the foot of the tower, is :
A
$$9\left( {1 + \sqrt 3 } \right)$$
B
$$18\left( {1 + \sqrt 3 } \right)$$
C
$$18\left( {\sqrt 3 - 1} \right)$$
D
$${9 \over 2}\left( {\sqrt 3 - 1} \right)$$
3
JEE Main 2018 (Offline)
+4
-1
Out of Syllabus
PQR is a triangular park with PQ = PR = 200 m. A T.V. tower stands at the mid-point of QR. If the angles of elevation of the top of the tower at P, Q and R are respectively 45$$^\circ$$, 30$$^\circ$$ and 30$$^\circ$$, then the height of the tower (in m) is :
A
$$50\sqrt 2$$
B
100
C
50
D
$$100\sqrt 3$$
4
JEE Main 2018 (Online) 15th April Evening Slot
+4
-1
Out of Syllabus
A tower T1 of height 60 m is located exactly opposite to a tower T2 of height 80 m on a straight road. Fromthe top of T1, if the angle of depression of the foot of T2 is twice the angle of elevation of the top of T2, then the width (in m) of the road between the feetof the towers T1 and T2 is :
A
$$10\sqrt 2$$
B
$$10\sqrt 3$$
C
$$20\sqrt 3$$
D
$$20\sqrt 2$$
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