1
JEE Main 2021 (Online) 17th March Evening Shift
+4
-1
Out of Syllabus
A block of mass 1 kg attached to a spring is made to oscillate with an initial amplitude of 12 cm. After 2 minutes the amplitude decreases to 6 cm. Determine the value of the damping constant for this motion . (take ln 2 = 0.693)
A
0.69 $$\times$$ 102 kg s$$-$$1
B
3.3 $$\times$$ 102 kg s$$-$$1
C
1.16 $$\times$$ 10$$-$$2 kg s$$-$$1
D
5.7 $$\times$$ 10$$-$$3 kg s$$-$$1
2
JEE Main 2021 (Online) 17th March Morning Shift
+4
-1
For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal ?
A
x = $${A \over 2}$$
B
x = $$\pm$$ A
C
x = $$\pm$$ $${A \over {\sqrt 2 }}$$
D
x = 0
3
JEE Main 2021 (Online) 16th March Evening Shift
+4
-1
Out of Syllabus
Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass = 500g, Decay constant = 20 g/s then how much time is required for the amplitude of the system to drop to drop to half of its initial value? (ln 2 = 0.693)
A
17.32 s
B
34.65 s
C
0.034 s
D
15.01 s
4
JEE Main 2021 (Online) 16th March Morning Shift
+4
-1
Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g/2, the time period of pendulum will be :
A
$$\sqrt 3 T$$
B
$$\sqrt {{2 \over 3}} T$$
C
$${T \over {\sqrt 3 }}$$
D
$$\sqrt {{3 \over 2}} T$$
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