1
JEE Main 2024 (Online) 1st February Evening Shift
Numerical
+4
-1
Change Language
For a certain reaction at $300 \mathrm{~K}, \mathrm{~K}=10$, then $\Delta \mathrm{G}^{\circ}$ for the same reaction is - ____________ $\times 10^{-1} \mathrm{~kJ} \mathrm{~mol}^{-1}$.

(Given $\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )
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2
JEE Main 2024 (Online) 1st February Evening Shift
Numerical
+4
-1
Change Language
The amount of electricity in Coulomb required for the oxidation of $1 \mathrm{~mol}$ of $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$ is __________ $\times 10^5 \mathrm{C}$.
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3
JEE Main 2024 (Online) 1st February Evening Shift
Numerical
+4
-1
Change Language
Following Kjeldahl's method, $1 \mathrm{~g}$ of organic compound released ammonia, that neutralised $10 \mathrm{~mL}$ of $2 \mathrm{M} ~\mathrm{H}_2 \mathrm{SO}_4$. The percentage of nitrogen in the compound is ___________ $\%$.
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4
JEE Main 2024 (Online) 1st February Evening Shift
Numerical
+4
-1
Change Language
Consider the following redox reaction :

$$ \mathrm{MnO}_4^{-}+\mathrm{H}^{+}+\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \rightleftharpoons \mathrm{Mn}^{2+}+\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2 $$

The standard reduction potentials are given as below $\left(\mathrm{E}_{\text {red }}^0\right)$ :

$$ \begin{aligned} & \mathrm{E}_{\mathrm{MnO}_4^{-} / \mathrm{Mn}^{2+}}^{\circ}=+1.51 \mathrm{~V} \\\\ & \mathrm{E}_{\mathrm{CO}_2 / \mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4}^{\circ}=-0.49 \mathrm{~V} \end{aligned} $$

If the equilibrium constant of the above reaction is given as $\mathrm{K}_{\mathrm{eq}}=10^x$, then the value of $x=$ __________ (nearest integer)
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