1
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The value of $${\left( {{{1 + \sin {{2\pi } \over 9} + i\cos {{2\pi } \over 9}} \over {1 + \sin {{2\pi } \over 9} - i\cos {{2\pi } \over 9}}}} \right)^3}$$ is

A
$$ - {1 \over 2}\left( {1 - i\sqrt 3 } \right)$$
B
$$ - {1 \over 2}\left( {\sqrt 3 - i} \right)$$
C
$${1 \over 2}\left( {1 - i\sqrt 3 } \right)$$
D
$${1 \over 2}\left( {\sqrt 3 + i} \right)$$
2
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If $$f(x) = {x^3} - {x^2}f'(1) + xf''(2) - f'''(3),x \in \mathbb{R}$$, then

A
$$2f(0) - f(1) + f(3) = f(2)$$
B
$$f(1) + f(2) + f(3) = f(0)$$
C
$$f(3) - f(2) = f(1)$$
D
$$3f(1) + f(2) = f(3)$$
3
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language

Let p and q be two statements. Then $$ \sim \left( {p \wedge (p \Rightarrow \, \sim q)} \right)$$ is equivalent to

A
$$\left( { \sim p} \right) \vee q$$
B
$$p \vee \left( {p \wedge ( \sim q)} \right)$$
C
$$p \vee \left( {p \wedge q} \right)$$
D
$$p \vee \left( {\left( { \sim p} \right) \wedge q} \right)$$
4
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$$\int\limits_{{{3\sqrt 2 } \over 4}}^{{{3\sqrt 3 } \over 4}} {{{48} \over {\sqrt {9 - 4{x^2}} }}dx} $$ is equal to :

A
$${\pi \over 2}$$
B
$${\pi \over 3}$$
C
$${\pi \over 6}$$
D
$$2\pi $$
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