1
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let $$\gamma_1$$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $$\gamma_2$$ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, $$\frac{\gamma_1}{\gamma_2}$$ is :

A
$$\frac{35}{27}$$
B
$$\frac{25}{21}$$
C
$$\frac{21}{25}$$
D
$$\frac{27}{35}$$
2
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

When a beam of white light is allowed to pass through convex lens parallel to principal axis, the different colours of light converge at different point on the principle axis after refraction. This is called :

A
Spherical aberration
B
Scattering
C
Polarisation
D
Chromatic aberration
3
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In an Isothermal change, the change in pressure and volume of a gas can be represented for three different temperature; $$\mathrm{T_3 > T_2 > T_1}$$ as :

A
JEE Main 2023 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 75 English Option 1
B
JEE Main 2023 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 75 English Option 2
C
JEE Main 2023 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 75 English Option 3
D
JEE Main 2023 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 75 English Option 4
4
JEE Main 2023 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$$\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$$

$$\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$$

Then the correct relation between E$$_0$$ and B$$_0$$ is given by

A
$$\mathrm{{E_o}{B_o} = \omega k}$$
B
$$\mathrm{{E_0} = k{B_0}}$$
C
$$\mathrm{k{E_0} = \omega {B_0}}$$
D
$$\mathrm{\omega {E_0} = k{B_0}}$$
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