1
JEE Main 2022 (Online) 26th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A velocity selector consists of electric field $$\vec{E}=E \,\hat{k}$$ and magnetic field $$\vec{B}=B \,\hat{j}$$ with $$B=12 \,m T$$. The value of $$E$$ required for an electron of energy $$728 \,\mathrm{e} V$$ moving along the positive $$x$$-axis to pass undeflected is :

(Given, mass of electron $$=9.1 \times 10^{-31} \mathrm{~kg}$$ )

A
$$192 \,\mathrm{kVm}^{-1}$$
B
$$192 \,\mathrm{mVm}^{-1}$$
C
$$9600 \,\mathrm{kVm}^{-1}$$
D
$$16 \,\mathrm{kVm}^{-1}$$
2
JEE Main 2022 (Online) 26th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Two masses $$M_{1}$$ and $$M_{2}$$ are tied together at the two ends of a light inextensible string that passes over a frictionless pulley. When the mass $$M_{2}$$ is twice that of $$M_{1}$$, the acceleration of the system is $$a_{1}$$. When the mass $$M_{2}$$ is thrice that of $$M_{1}$$, the acceleration of the system is $$a_{2}$$. The ratio $$\frac{a_{1}}{a_{2}}$$ will be :

JEE Main 2022 (Online) 26th July Evening Shift Physics - Laws of Motion Question 33 English

A
$$\frac{1}{3}$$
B
$$\frac{2}{3}$$
C
$$\frac{3}{2}$$
D
$$\frac{1}{2}$$
3
JEE Main 2022 (Online) 26th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language

Mass numbers of two nuclei are in the ratio of $$4: 3$$. Their nuclear densities will be in the ratio of

A
4 : 3
B
$$\left(\frac{3}{4}\right)^{\frac{1}{3}}$$
C
1 : 1
D
$$\left(\frac{4}{3}\right)^{\frac{1}{3}}$$
4
JEE Main 2022 (Online) 26th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The area of cross section of the rope used to lift a load by a crane is $$2.5 \times 10^{-4} \mathrm{~m}^{2}$$. The maximum lifting capacity of the crane is 10 metric tons. To increase the lifting capacity of the crane to 25 metric tons, the required area of cross section of the rope should be :

(take $$g=10 \,m s^{-2}$$ )

A
$$6.25\times 10^{-4} \mathrm{~m}^{2}$$
B
$$10\times 10^{-4} \mathrm{~m}^{2}$$
C
$$1\times 10^{-4} \mathrm{~m}^{2}$$
D
$$1.67\times 10^{-4} \mathrm{~m}^{2}$$
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