1
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the following reactions sequence, structure of A and B respectively will be :
JEE Main 2020 (Online) 7th January Evening Slot Chemistry - Hydrocarbons Question 88 English
A
JEE Main 2020 (Online) 7th January Evening Slot Chemistry - Hydrocarbons Question 88 English Option 1
B
JEE Main 2020 (Online) 7th January Evening Slot Chemistry - Hydrocarbons Question 88 English Option 2
C
JEE Main 2020 (Online) 7th January Evening Slot Chemistry - Hydrocarbons Question 88 English Option 3
D
JEE Main 2020 (Online) 7th January Evening Slot Chemistry - Hydrocarbons Question 88 English Option 4
2
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the following reactions

JEE Main 2020 (Online) 7th January Evening Slot Chemistry - Haloalkanes and Haloarenes Question 103 English
Ks and Ke, are respectively, the rate constants for substitution and elimination and $$\mu = {{{k_s}} \over {{k_e}}}$$ the correct options is
A
$${\mu _B} > {\mu _A}$$ and Ke(A) > Ke(B)
B
$${\mu _A} > {\mu _B}$$ and Ke(B) > Ke(A)
C
$${\mu _B} > {\mu _A}$$ and Ke(B) > Ke(A)
D
$${\mu _A} > {\mu _B}$$ and Ke(A) > Ke(B)
3
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The number of possible optical isomers for the complexes MA2B2 with sp3 and dsp2 hydridized metal atom. respectively, is :
Note : A and B are unidentate netural and unidentate monoanionic ligands, respectively.
A
0 and 2
B
0 and 0
C
0 and 1
D
2 and 2
4
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The equation that is incorrect is :
A
$${\left( {\Lambda _m^0} \right)_{KCl}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$
B
$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaI}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$
C
$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{KCl}}$$
D
$${\left( {\Lambda _m^0} \right)_{{H_2}O}} = {\left( {\Lambda _m^0} \right)_{HCl}} + {\left( {\Lambda _m^0} \right)_{NaOH}} - {\left( {\Lambda _m^0} \right)_{NaCl}}$$
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