1
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $${{3 + i\sin \theta } \over {4 - i\cos \theta }}$$, $$\theta $$ $$ \in $$ [0, 2$$\theta $$], is a real number, then an argument of
sin$$\theta $$ + icos$$\theta $$ is :
A
$$\pi - {\tan ^{ - 1}}\left( {{3 \over 4}} \right)$$
B
$$ - {\tan ^{ - 1}}\left( {{3 \over 4}} \right)$$
C
$${\tan ^{ - 1}}\left( {{4 \over 3}} \right)$$
D
$$\pi - {\tan ^{ - 1}}\left( {{4 \over 3}} \right)$$
2
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\theta $$1 and $$\theta $$2 be respectively the smallest and the largest values of $$\theta $$ in (0, 2$$\pi $$) - {$$\pi $$} which satisfy the equation,
2cot2$$\theta $$ - $${5 \over {\sin \theta }}$$ + 4 = 0, then
$$\int\limits_{{\theta _1}}^{{\theta _2}} {{{\cos }^2}3\theta d\theta } $$ is equal to :
A
$${\pi \over 9}$$
B
$${{2\pi } \over 3}$$
C
$${{\pi } \over 3}$$
D
$${\pi \over 3} + {1 \over 6}$$
3
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let y = y(x) be a function of x satisfying

$$y\sqrt {1 - {x^2}} = k - x\sqrt {1 - {y^2}} $$ where k is a constant and

$$y\left( {{1 \over 2}} \right) = - {1 \over 4}$$. Then $${{dy} \over {dx}}$$ at x = $${1 \over 2}$$, is equal to :
A
$${2 \over {\sqrt 5 }}$$
B
$$ - {{\sqrt 5 } \over 2}$$
C
$${{\sqrt 5 } \over 2}$$
D
$$ - {{\sqrt 5 } \over 4}$$
4
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$\overrightarrow a $$ , $$\overrightarrow b $$ and $$\overrightarrow c $$ be three unit vectors such that
$$\overrightarrow a + \vec b + \overrightarrow c = \overrightarrow 0 $$. If $$\lambda = \overrightarrow a .\vec b + \vec b.\overrightarrow c + \overrightarrow c .\overrightarrow a $$ and
$$\overrightarrow d = \overrightarrow a \times \vec b + \vec b \times \overrightarrow c + \overrightarrow c \times \overrightarrow a $$, then the ordered pair, $$\left( {\lambda ,\overrightarrow d } \right)$$ is equal to :
A
$$\left( {{3 \over 2},3\overrightarrow a \times \overrightarrow c } \right)$$
B
$$\left( { - {3 \over 2},3\overrightarrow c \times \overrightarrow b } \right)$$
C
$$\left( { - {3 \over 2},3\overrightarrow a \times \overrightarrow b } \right)$$
D
$$\left( {{3 \over 2},3\overrightarrow b \times \overrightarrow c } \right)$$
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