1
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently the mean collision time between the gas molecule changes from $${\tau _1}$$ to $${\tau _2}$$ . If $${{{C_p}} \over {{C_v}}} = \gamma $$ for this gas then a good estimate for $${{{\tau _2}} \over {{\tau _1}}}$$ is given by :
A
$${\left( 2 \right)^{{{1 + \gamma } \over 2}}}$$
B
2
C
$${\left( {{1 \over 2}} \right)^{{{1 + \gamma } \over 2}}}$$
D
$${\left( {{1 \over 2}} \right)^\gamma }$$
2
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The dimension of $${{{B^2}} \over {2{\mu _0}}}$$, where B is magnetic field and $${{\mu _0}}$$ is the magnetic permeability of vacuum, is :
A
ML2T–2
B
MLT–2
C
ML-1T–2
D
ML2T–1
3
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the figure, potential difference between A and B is : JEE Main 2020 (Online) 7th January Evening Slot Physics - Semiconductor Question 176 English
A
10 V
B
5 V
C
zero
D
15 V
4
JEE Main 2020 (Online) 7th January Evening Slot
Numerical
+4
-0
Change Language
The sum of two forces $$\overrightarrow P $$ and $$\overrightarrow Q $$ is $$\overrightarrow R $$ such that $$\left| {\overrightarrow R } \right| = \left| {\overrightarrow P } \right|$$ . The angle $$\theta $$ (in degrees) that the resultant of 2$${\overrightarrow P }$$ and $${\overrightarrow Q }$$ will make with $${\overrightarrow Q }$$ is , ..............
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