1
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The shortest wavelength of H atom in the Lyman series is $$\lambda $$1. The longest wavelength in the Balmar series of He+ is :
A
$${{5{\lambda _1}} \over 9}$$
B
$${{36{\lambda _1}} \over 5}$$
C
$${{27{\lambda _1}} \over 5}$$
D
$${{9{\lambda _1}} \over 5}$$
2
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Five moles of an ideal gas at 1 bar and 298 K is expanded into vacuum to double the volume. The work done is :
A
Zero
B
-RT $$\ln {{{V_2}} \over {{V_1}}}$$
C
CV (T2 – T1)
D
– RT (V2 – V1)
3
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product [B] in the following reactions is : JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Alcohols, Phenols and Ethers Question 115 English
A
CH3 – CH2 – CH = CH – CH3
B
CH2 = CH2
C
JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Alcohols, Phenols and Ethers Question 115 English Option 3
D
JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Alcohols, Phenols and Ethers Question 115 English Option 4
4
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the equilibrium constant for
A ⇌ B + C is $$K_{eq}^{(1)}$$ and that of
B + C ⇌ P is $$K_{eq}^{(2)}$$, the equilibrium
constant for A ⇌ P is :
A
$${{K_{eq}^{(1)}} \over {K_{eq}^{(2)}}}$$
B
$${K_{eq}^{(1)}}$$ + $${K_{eq}^{(2)}}$$
C
$${K_{eq}^{(2)}}$$ - $${K_{eq}^{(1)}}$$
D
$${K_{eq}^{(1)}}$$ $${K_{eq}^{(2)}}$$
JEE Main Papers
2023
2021
EXAM MAP