1
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The shortest wavelength of H atom in the Lyman series is $$\lambda $$1. The longest wavelength in the Balmar series of He+ is :
A
$${{5{\lambda _1}} \over 9}$$
B
$${{36{\lambda _1}} \over 5}$$
C
$${{27{\lambda _1}} \over 5}$$
D
$${{9{\lambda _1}} \over 5}$$
2
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the equilibrium constant for
A ⇌ B + C is $$K_{eq}^{(1)}$$ and that of
B + C ⇌ P is $$K_{eq}^{(2)}$$, the equilibrium
constant for A ⇌ P is :
A
$${{K_{eq}^{(1)}} \over {K_{eq}^{(2)}}}$$
B
$${K_{eq}^{(1)}}$$ + $${K_{eq}^{(2)}}$$
C
$${K_{eq}^{(2)}}$$ - $${K_{eq}^{(1)}}$$
D
$${K_{eq}^{(1)}}$$ $${K_{eq}^{(2)}}$$
3
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The reaction in which the hybridisation of the underlined atom is affected is :
A
JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 145 English Option 1
B
JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 145 English Option 2
C
JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 145 English Option 3
D
JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 145 English Option 4
4
JEE Main 2020 (Online) 4th September Evening Slot
Numerical
+4
-0
Change Language
A test consists of 6 multiple choice questions, each having 4 alternative answers of which only one is correct. The number of ways, in which a candidate answers all six questions such that exactly four of the answers are correct, is __________.
Your input ____
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