1
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let ƒ : [0, 2] $$ \to $$ R be a twice differentiable function such that ƒ''(x) > 0, for all x $$ \in $$ (0, 2). If $$\phi $$(x) = ƒ(x) + ƒ(2 – x), then $$\phi $$ is :
A
decreasing on (0, 2)
B
decreasing on (0, 1) and increasing on (1, 2)
C
increasing on (0, 2)
D
increasing on (0, 1) and decreasing on (1, 2)
2
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let O(0, 0) and A(0, 1) be two fixed points. Then the locus of a point P such that the perimeter of $$\Delta $$AOP is 4, is :
A
9x2 + 8y2 – 8y = 16
B
8x2 – 9y2 + 9y = 18
C
8x2 + 9y2 – 9y = 18
D
9x2 – 8y2 + 8y = 16
3
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
$$\mathop {\lim }\limits_{x \to 0} {{{{\sin }^2}x} \over {\sqrt 2 - \sqrt {1 + \cos x} }}$$ equals:
A
$$ \sqrt 2$$
B
$$2 \sqrt 2$$
C
4
D
$$4 \sqrt 2$$
4
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\alpha $$ and $$\beta $$ be the roots of the equation x2 – 2x + 2 = 0, then the least value of n for which $${\left( {{\alpha \over \beta }} \right)^n} = 1$$ is :
A
2
B
5
C
4
D
3

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