1
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The sum of the squares of the lengths of the chords intercepted on the circle, x2 + y2 = 16, by the lines, x + y = n, n $$ \in $$ N, where N is the set of all natural numbers, is :
A
210
B
160
C
320
D
105
2
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in :
A
1st and 2nd qudratants
B
4th qudratant
C
1st and 2nd and 4th qudratants
D
1st qudratant
3
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be :
A
20 cm from the convergent mirror, same size as the object
B
40 cm from the convergent mirror, same size as the object
C
40 cm from the convergent lens, same size as the object
D
20 cm from the convergent mirror, twice the size of the object
4
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two particles move at right angle to each other. Their de-Broglie wavelengths are $$\lambda _1$$ and $$\lambda _2$$ respectively. The particles suffer perfectly inelastic collision. The de-Broglie wavelength $$\lambda _2$$ of the final particle, is given by :
A
$$\lambda = {{{\lambda _1} + {\lambda _2}} \over 2}$$
B
$${1 \over {{\lambda ^2}}} = {1 \over {\lambda _1^2}} + {1 \over {\lambda _2^2}}$$
C
$$\lambda = \sqrt {{\lambda _1}{\lambda _2}} $$
D
$${2 \over \lambda } = {1 \over {{\lambda _1}}} + {1 \over {{\lambda _2}}}$$

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