1
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The lathanide ion that would show colour is :
A
Sm3+
B
Gd3+
C
Lu3+
D
La3+
2
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Given that $${E^\Theta }_{{O_2}/{H_2}O} = 1.23\,V$$ ;

$${E^\Theta }_{{S_2}O_8^{2 - }/SO_4^{2 - }} = 2.05\,V$$

$${E^\Theta }_{B{r_2}/B{r^ - }} = 1.09\,V$$

$${E^\Theta }_{A{u^{3 + }}/Au} = 1.4\,V$$

The strongest oxidizing agent is :
A
O2
B
Au3+
C
Br2
D
$${S_2}O_8^{2 - }$$
3
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product of the following reaction is : JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 145 English
A
JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 145 English Option 1
B
JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 145 English Option 2
C
JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 145 English Option 3
D
JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Alcohols, Phenols and Ethers Question 145 English Option 4
4
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In order to oxidise a mixture of one mole of each of FeC2O4, Fe2(C2O4)3, FeSO4 and Fe2(SO4)3 in acidic medium, the number of moles of KMnO4 required is :
A
1.5
B
3
C
2
D
1

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