1
JEE Main 2017 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
The moment of inertia of a uniform cylinder of length $$l$$ and radius R about its perpendicular bisector is $$I$$. What is the ratio $${l \over R}$$ such that the moment of inertia is minimum?
A
$${3 \over {\sqrt 2 }}$$
B
$$\sqrt {{3 \over 2}} $$
C
$${{\sqrt 3 } \over 2}$$
D
1
2
JEE Main 2017 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be:

JEE Main 2017 (Offline) Physics - Capacitor Question 153 English
A
$$CE{{{r_1}} \over {({r_1} + r)}}$$
B
CE
C
$$CE{{{r_1}} \over {({r_2} + r)}}$$
D
$$CE{{{r_2}} \over {(r + {r_2})}}$$
3
JEE Main 2017 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
An electric dipole has a fixed dipole moment $$\overrightarrow p $$, which makes angle $$\theta$$ with respect to x-axis. When subjected to an electric field $$\mathop {{E_1}}\limits^ \to = E\widehat i$$ , it experiences a torque $$\overrightarrow {{T_1}} = \tau \widehat k$$ . When subjected to another electric field $$\mathop {{E_2}}\limits^ \to = \sqrt 3 {E_1}\widehat j$$ it experiences a torque $$\mathop {{T_2}}\limits^ \to = \mathop { - {T_1}}\limits^ \to $$ . The angle $$\theta$$ is:
A
90o
B
45o
C
30o
D
60o
4
JEE Main 2017 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
In a Young’s double slit experiment, slits are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide is
A
15.6 mm
B
1.56 mm
C
7.8 mm
D
9.75 mm

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