1
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
Two short bar magnets of length $$1$$ $$cm$$ each have magnetic moments $$1.20$$ $$A{m^2}$$ and $$1.00$$ $$A{m^2}$$ respectively. They are placed on a horizontal table parallel to each other with their $$N$$ poles pointing towards the South. They have a common magnetic equator and are separated by a distance of $$20.0$$ $$cm.$$ The value of the resultant horizontal magnetic induction at the mid-point $$O$$ of the line joining their centres is close to $$\left( \, \right.$$ Horizontal component of earth's magnetic induction is $$3.6 \times 10.5Wb/{m^2})$$
A
$$3.6 \times 10.5\,\,Wb/{m^2}$$
B
$$2.56 \times 10.4\,\,Wb/{m^2}$$
C
$$3.50 \times 10.4\,\,Wb/{m^2}$$
D
$$5.80 \times 10.4\,Wb/{m^2}$$
2
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
This questions has Statement - $${\rm I}$$ and Statement - $${\rm I}$$$${\rm I}$$. Of the four choices given after the Statements, choose the one that best describes into two Statements.

Statement - $${\rm I}$$ : Higher the range, greater is the resistance of ammeter.
Statement - $${\rm I}$$$${\rm I}$$ : To increase the range of ammeter, additional shunt needs to be used across it.

A
Statement - $${\rm I}$$ is true, Statement - $${\rm II}$$ is true, Statement - $${\rm II}$$ is the correct explanation of statement - $${\rm I}$$.
B
Statement - $${\rm I}$$ is true, Statement - $${\rm II}$$ is true, Statement - $${\rm II}$$ is not the correct explanation of statement - $${\rm I}$$.
C
Statement - $${\rm I}$$ is true, Statement - $${\rm II}$$ is false
D
Statement - $${\rm I}$$ is false, Statement - $${\rm II}$$ is true
3
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
The supply voltage to room is $$120V.$$ The resistance of the lead wires is $$6\Omega $$. A $$60$$ $$W$$ bulb is already switched on. What is the decrease of voltage across the bulb, when a $$240$$ $$W$$ heater is switched on in parallel to the bulb?
A
zero
B
$$2.9$$ Volt
C
$$13.3$$ Volt
D
$$10.04$$ Volt
4
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
Two capacitors $${C_1}$$ and $${C_2}$$ are charged to $$120$$ $$V$$ and $$200$$ $$V$$ respectively. It is found that connecting them together the potential on each one can be made zero. Then
A
$$5{C_1} = 3{C_2}$$
B
$$3{C_1} = 5{C_2}$$
C
$$3{C_1} + 5{C_2} = 0$$
D
$$9{C_1} = 4{C_2}$$
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