1
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
An ideal gas enclosed in a vertical cylindrical container supports a freely moving piston of mass $$M.$$ The piston and the cylinder have equal cross sectional area $$A$$. When the piston is in equilibrium, the volume of the gas is $${V_0}$$ and its pressure is $${P_0}.$$ The piston is slightly displaced from the equilibrium position and released,. Assuming that the system is completely isolated from its surrounding, the piston executes a simple harmonic motion with frquency
A
$${1 \over {2\pi }}\,{{A\gamma {P_0}} \over {{V_0}M}}$$
B
$${1 \over {2\pi }}\,{{{V_0}M{P_0}} \over {{A^2}\gamma }}$$
C
$${1 \over {2\pi }}\,\sqrt {{{A\gamma {P_0}} \over {{V_0}M}}} $$
D
$${1 \over {2\pi }}\,\sqrt {{{M{V_0}} \over {A\gamma {P_0}}}} $$
2
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
JEE Main 2013 (Offline) Physics - Heat and Thermodynamics Question 343 English

The above $$p$$-$$v$$ diagram represents the thermodynamic cycle of an engine, operating with an ideal monatomic gas. The amount of heat, extracted from the source in a single cycle is

A
$${p_0}{v_0}$$
B
$$\left( {{{13} \over 2}} \right){p_0}{v_0}$$
C
$$\left( {{{11} \over 2}} \right){p_0}{v_0}$$
D
$$4{p_0}{v_0}$$
3
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
Assume that a drop of liquid evaporates by decreases in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible ? The surface tension is $$T,$$ density of liquid is $$\rho $$ and $$L$$ is its latent heat of vaporization.
A
$$\rho L/T$$
B
$$\sqrt {T/\rho L} $$
C
$$T/\rho L$$
D
$$2T/\rho L$$
4
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
A uniform cylinder of length $$L$$ and mass $$M$$ having cross-sectional area $$A$$ is suspended, with its length vertical, from a fixed point by a mass-less spring such that it is half submerged in a liquid of density $$\sigma $$ at equilibrium position. The extension $${x_0}$$ of the spring when it is in equilibrium is:
A
$${{Mg} \over k}$$
B
$${{Mg} \over k}\left( {1 - {{LA\sigma } \over M}} \right)$$
C
$${{Mg} \over k}\left( {1 - {{LA\sigma } \over {2M}}} \right)$$
D
$${{Mg} \over k}\left( {1 + {{LA\sigma } \over M}} \right)$$
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