1
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
JEE Main 2013 (Offline) Physics - Heat and Thermodynamics Question 343 English

The above $$p$$-$$v$$ diagram represents the thermodynamic cycle of an engine, operating with an ideal monatomic gas. The amount of heat, extracted from the source in a single cycle is

A
$${p_0}{v_0}$$
B
$$\left( {{{13} \over 2}} \right){p_0}{v_0}$$
C
$$\left( {{{11} \over 2}} \right){p_0}{v_0}$$
D
$$4{p_0}{v_0}$$
2
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
If a piece of metal is heated to temperature $$\theta $$ and then allowed to cool in a room which is at temperature $${\theta _0},$$ the graph between the temperature $$T$$ of the metal and time $$t$$ will be closest to
A
JEE Main 2013 (Offline) Physics - Properties of Matter Question 225 English Option 1
B
JEE Main 2013 (Offline) Physics - Properties of Matter Question 225 English Option 2
C
JEE Main 2013 (Offline) Physics - Properties of Matter Question 225 English Option 3
D
JEE Main 2013 (Offline) Physics - Properties of Matter Question 225 English Option 4
3
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
An ideal gas enclosed in a vertical cylindrical container supports a freely moving piston of mass $$M.$$ The piston and the cylinder have equal cross sectional area $$A$$. When the piston is in equilibrium, the volume of the gas is $${V_0}$$ and its pressure is $${P_0}.$$ The piston is slightly displaced from the equilibrium position and released,. Assuming that the system is completely isolated from its surrounding, the piston executes a simple harmonic motion with frquency
A
$${1 \over {2\pi }}\,{{A\gamma {P_0}} \over {{V_0}M}}$$
B
$${1 \over {2\pi }}\,{{{V_0}M{P_0}} \over {{A^2}\gamma }}$$
C
$${1 \over {2\pi }}\,\sqrt {{{A\gamma {P_0}} \over {{V_0}M}}} $$
D
$${1 \over {2\pi }}\,\sqrt {{{M{V_0}} \over {A\gamma {P_0}}}} $$
4
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
The amplitude of a damped oscillator decreases to $$0.9$$ times its original magnitude in $$5s$$. In another $$10s$$ it will decrease to $$\alpha $$ times its original magnitude, where $$\alpha $$ equals
A
$$0.7$$
B
$$0.81$$
C
$$0.729$$
D
$$0.6$$
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