1
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
A ray of light along $$x + \sqrt 3 y = \sqrt 3 $$ gets reflected upon reaching $$X$$-axis, the equation of the reflected ray is :
A
$$y = x + \sqrt 3 $$
B
$$\sqrt 3 y = x - \sqrt 3 $$
C
$$y = \sqrt 3 x - \sqrt 3 $$
D
$$\sqrt 3 y = x - 1$$
2
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
The $$x$$-coordinate of the incentre of the triangle that has the coordinates of mid points of its sides as $$(0, 1) (1, 1)$$ and $$(1, 0)$$ is :
A
$$2 + \sqrt 2 $$
B
$$2 - \sqrt 2 $$
C
$$1 + \sqrt 2 $$
D
$$1 - \sqrt 2 $$
3
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
The circle passing through $$(1, -2)$$ and touching the axis of $$x$$ at $$(3, 0)$$ also passes through the point :
A
$$\left( { - 5,\,2} \right)$$
B
$$\left( { 2,\,-5} \right)$$
C
$$\left( { 5,\,-2} \right)$$
D
$$\left( { - 2,\,5} \right)$$
4
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
The equation of the circle passing through the foci of the ellipse $${{{x^2}} \over {16}} + {{{y^2}} \over 9} = 1$$, and having centre at $$(0,3)$$ is :
A
$${x^2} + {y^2} - 6y - 7 = 0$$
B
$${x^2} + {y^2} - 6y + 7 = 0$$
C
$${x^2} + {y^2} - 6y - 5 = 0$$
D
$${x^2} + {y^2} - 6y + 5 = 0$$
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