1
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
Statement - 1 : The point $$A(1,0,7)$$ is the mirror image of the point

$$B(1,6,3)$$ in the line : $${x \over 1} = {{y - 1} \over 2} = {{z - 2} \over 3}$$

Statement - 2 : The line $${x \over 1} = {{y - 1} \over 2} = {{z - 2} \over 3}$$ bisects the line

segment joining $$A(1,0,7)$$ and $$B(1, 6, 3)$$
A
Statement -1 is true, Statement -2 is true; Statement -2 is not a correct explanation for Statement -1.
B
Statement -1 is true, Statement - 2 is false.
C
Statement - 1 is false , Statement -2 is true.
D
Statement -1 is true, Statement -2 is true; Statement -2 is a correct explanation for Statement -1.
2
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
If $$\overrightarrow a = {1 \over {\sqrt {10} }}\left( {3\widehat i + \widehat k} \right)$$ and $$\overrightarrow b = {1 \over 7}\left( {2\widehat i + 3\widehat j - 6\widehat k} \right),$$ then the value

of $$\left( {2\overrightarrow a - \overrightarrow b } \right)\left[ {\left( {\overrightarrow a \times \overrightarrow b } \right) \times \left( {\overrightarrow a + 2\overrightarrow b } \right)} \right]$$ is :
A
$$-3$$
B
$$5$$
C
$$3$$
D
$$-5$$
3
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
The domain of the function f(x) = $${1 \over {\sqrt {\left| x \right| - x} }}$$ is
A
$$\left( {0,\infty } \right)$$
B
$$\left( { - \infty ,0} \right)$$
C
$$\left( { - \infty ,\infty } \right) - \left\{ 0 \right\}$$
D
$$\left( { - \infty ,\infty } \right)$$
4
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
$$\mathop {\lim }\limits_{x \to 2} \left( {{{\sqrt {1 - \cos \left\{ {2(x - 2)} \right\}} } \over {x - 2}}} \right)$$
A
Equals $$\sqrt 2 $$
B
Equals $$-\sqrt 2 $$
C
Equals $${1 \over {\sqrt 2 }}$$
D
does not exist
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