All the members exhibit +3 oxidation state

Because of similar properties the separation of lanthanoids is not easy.

Availability of 4f electrons results in the formation of compounds in +4 state for all the members of the series.

There is a gradual decrease in the radii of the members with increasing atomic number in the series.

Nitrogen cannot form $$d\pi - p\pi$$ bond.

Single N – N bond is weaker than the single P – P bond

N₂O₄ has two resonance structures

The stability of hydrides increases from NH₃ to BiH₃ in group 15 of the periodic table

p(H₂) = 1 atm and [H⁺] = 1.0 M

p(H₂) = 1 atm and [H⁺] = 2.0 M

p(H₂) = 2 atm and [H⁺] =1.0 M

p(H₂) = 2 atm and [H⁺] =2.0 M

sp , sp², sp³

sp², sp , sp³

sp , sp³, sp²

sp², sp³, sp